Answer to Question #89539 in General Chemistry for sam

Question

the amount in moles when 0.256 g of aluminum hydroxide is weighed on an electronic balance.

Answer 1

The amount in moles n = m/M;

m - mass;

M - molar mass.

M(Al(OH)₃) = 78 g/mol.

n = 0.256 / 78 = 0.00328 mol = 3.28 mmol