n(MgCl2) = m(MgCl2) / M(MgCl2) = 5.56 g / 95 g mol-1 = 0.0585 mol.
Vs(MgCl2) = n(MgCl2) / C(MgCl2) = 0.0585 mol / 0.250 M = 0.234 L = 234 mL.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment