Answer to Question #88725 in General Chemistry for obasi

Question

calculate the root mean square of bromine molecules at 23 degree celcius and 1.00atm.What is the root mean square of the same gas at 23 degree celcius and 1.5atm?

Answer 1

Calculate the root mean square of bromine molecules at 23 degree celcius and 1.00atm.What is the root mean square of the same gas at 23 degree celcius and 1.5atm?

Solution:

U_rms=$\sqrt{\smash[b]{3p/ρ}}$ ;

1.$\rho$ =p*M/R*T; M(Br2)=2*80=160 grams/mol; R=0,08206 atm*L/mol*K; T=23+273=296 K;

$\rho$=1*160/0,08206*296=6,587 grams/L;

U_rms=$\sqrt{\smash[b]{3*1/6,587}}$ =0,4554 m/s.

2.$\rho$=1,5*160/0,08206*296=9,88 grams/L;

U_rms=$\sqrt{\smash[b]{3*1,5/9,88}}$ =0,4555 m/s.

Answer: 0,4554 m/s; 0,4555 m/s.