Answer to Question #88633 in General Chemistry for Lim Yoona

Question

Students took 2.5 ml of a leaf extract and using column chromatography they separated carotene from chlorophyll. The students collected carotene in a volumetric flask and made up their sample to the 25 mL line on the volumetric flask with hexane:acetone (3:2).

The student measured the absorbance of the purified carotene (collected in the volumetric flask), and found that it corresponded to a concentration of 0.031 mg mL-1. What was the concentration carotene in the original leaf extract in mg mL-1 ?

Answer 1

$\Delta V = 25mL/2.5mL =10$

$c(carotene)= 0.031mg/mL*10=0.31mg/mL$