Question #88633

Students took 2.5 ml of a leaf extract and using column chromatography they separated carotene from chlorophyll. The students collected carotene in a volumetric flask and made up their sample to the 25 mL line on the volumetric flask with hexane:acetone (3:2).

The student measured the absorbance of the purified carotene (collected in the volumetric flask), and found that it corresponded to a concentration of 0.031 mg mL-1. What was the concentration carotene in the original leaf extract in mg mL-1 ?

Expert's answer

ΔV=25mL/2.5mL=10\Delta V = 25mL/2.5mL =10

c(carotene)=0.031mg/mL10=0.31mg/mLc(carotene)= 0.031mg/mL*10=0.31mg/mL



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