Answer to Question #88160 in General Chemistry for Kori

General Chemistry

Question #88160

What is the mass of ammonium chloride is 500.0mL of a 0.198M solution?

Expert's answer

500mL=0.5L

"n(NH4Cl)=0.5L*0.198mol\/L=0.099mol"

"53.49g\/mol*0.099moles=5.295g"

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