Question #88159
what is the mass of ammonium chloride is 500.0mL of a 0.198M solution?
1
Expert's answer
2019-04-17T04:25:09-0400

1000mL contain 0.198moles

500mL contain ?moles

500mL∗0.198M/1000mL=0.099500mL*0.198M/1000mL=0.099

53.49g/mol∗0.099mol=5.295g(NH4Cl)53.49g/mol*0.099mol=5.295g(NH4Cl)


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