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Answer to Question #88156 in General Chemistry for Carrie Fowle
Question #88156
How much 6.0 M NaOH is necessary to prepare 500 mL of a 0.050 M solution of NaOH?
Expert's answer
500mL(0.5L) 0.05M NaOH contain "0.05mol\/L*0.5L=0.025moles(NaOH)"
1L contain 6 moles
?L contain 0.025moles
"\\dfrac{0.025moles}{6 mol\/L}=0.00416L=4.16mL"
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