Question

How much 6.0 M NaOH is necessary to prepare 500 mL of a 0.050 M solution of NaOH?

Answer 1

500mL(0.5L) 0.05M NaOH contain $0.05mol/L*0.5L=0.025moles(NaOH)$

1L contain 6 moles

?L contain 0.025moles

$\dfrac{0.025moles}{6 mol/L}=0.00416L=4.16mL$