Question #88121
titanium metal from its oxide according to the following balanced equation: TiO2 + 2C >> Ti(s)+ 2CO(g) when 30.6 kg of C reacts with 76.2 kg of TiO2, 39.8 kg of Ti is produced. Find the limiting reactant, theoretical yield ( in kg) and the percent yield.
1
Expert's answer
2019-04-17T04:16:21-0400

TiO2(s)+2C(s)2CO(g)+Ti(s)TiO2(s)+2C(s) \to 2CO(g)+Ti(s)

n(C)=30600g12g/mol=2550molesn(C)=\dfrac{30600g}{12g/mol}=2550moles

n(TiO2)=76200g79.86g/mol=954.17moles(limiting)n(TiO2)=\dfrac{76200g}{79.86g/mol}=954.17moles(limiting)

76200g47.867g/mol79.86g/mol=45673.25g\dfrac{76200g*47.867g/mol}{79.86g/mol }=45673.25g

%yield=\dfrac{39800g}{45673.25g}*100=87.14%

%yield= %yield=39800g45673.25100=87.14\dfrac{39800g}{45673.25}*100=87.14 %



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