Question

A 2.50-L volume of hydrogen measured at –196 °C is warmed to 100 °C. Calculate the volume of the
gas at the higher temperature, assuming no change in pressure.

Answer 1

According to the ideal gas law:

P₁V₁/T₁ = P₂V₂/T₂,

where P - pressure, V - volume, T - temperature.

As the pressure is constant:

V₁/T₁ = V₂/T₂.

From here:

V₂ = V₁T₂/T₁

Here, V₁ = 2.50 L, T₁ = -196°C = 77.15 K, T₂ = 100°C = 373.15 K.

As a result,

V₂ = 2.5 L × 373.15 K / 77.15 K = 12.1 L

Answer: 12.1 L.