HA+A=0.05
A/HA=0.063
HA=0.047M
A=0.003M
This means, you need to put 0.047 moles of KH2PO4 and 0.003 moles of K2HPO4 salts into 1 liters of solution.
for molecular weights: KH2PO4= 39+97=136amu; K2HPO4= 39*2+96=174amu
Thus, 0.047*136=6.392g of KH2PO4 and 0.003*174= 0.522g of K2HPO4 should be added.
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