2Li + 3N2 = 2Li3N
n(Li) = m / M = 2635 / 7 = 376.4 (mol)
pV = nRT
n = pV/RT = (799934.2 * 0.245) / (8.314 * 281) = 83.9 (mol)
N2 is the limiting reagent
n(Li3N) = n(N2) * 2 / 3 = 55.9 (mol)
m(Li3N) = n * M = 55.9 * 34.8 = 1945.32 (g)
Answer: m(Li3N) = = 1945.32 (g), N2 is the limiting reagent
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