During the electrolysis of water the following processes occur
Cathode (-) 2 +2 e=
Anode (+) 4O - 4e= +2O
Total electrolysis equation will be
2 O= 2 +
Find the amount of substance of water
. n (O)= = = 2 mol
Mr (O) = 2Ar (H) +Ar (O) =2×1 +16=18
.n () = n (O) = 2 mol
.m () = n Mr () = 2×2=4 g
Mr () = 2 Ar (H) = 2×1=2
Answer .m () = 4 g
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