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Answer to Question #87709 in General Chemistry for Karla
Question #87709
What’s the percentage of pbcl2 ?
Expert's answer
Solution.
PbCl2
M(PbCl2) = 278,11 g/mole
Firstly, we find the mass fraction of lead by the following formula:
w(Pb) = (1*207,2*100%)/278,11 = 74,50%
w(Cl) = 100%-74,50% = 25,50%
Answer:
w(Pb) = (1*207,2*100%)/278,11 = 74,50%
w(Cl) = 100%-74,50% = 25,50%
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