Answer to Question #87476 in General Chemistry for taha

Question

The reaction of hydrogen chloride(g) with ammonia(g) to form ammonium chloride(s) proceeds as follows:
HCl(g) + NH3(g) NH4Cl(s)
When 12.8 grams of HCl(g) react with sufficient NH3(g) , 61.8 kJ of energy are evolved .

What is the value of H for the chemical equation given?

ΔHrxn = ________ kJ

Answer 1

n(HCl) = 12.8g/36.5g/mol = 0.35 mol

∆Hrxn = 61.8kJ*1mol/0.35mol = 176.6 kJ

∆Hrxn = 176.6 kJ