Answer to Question #87475 in General Chemistry for taha

Question

The reaction of carbon dioxide(g) with hydrogen(g) to form acetylene(g) (C2H2) and water(g) proceeds as follows:
2 CO2(g) + 5 H2(g) C2H2(g) + 4 H2O(g)
When 15.8 grams of CO2(g) react with sufficient H2(g) , 8.35 kJ of energy are absorbed .

What is the value of H for the chemical equation given?

ΔHrxn = ________ kJ

Answer 1

$n=\frac{m}{M}$

$n(CO_2)=\frac{15.8g}{44\frac{g}{mol}}=0.359 mol$

When 0.359 mol of $CO_2$ react with sufficient amount of $H_2$ 8.35 kJ of energy are absorbed.

When 2 moles of $CO_2$ react with sufficient amount of $H_2$ xkJ of enerhy is absorbed.

Solve the proportion:

$\frac{0.359 mol}{2 mol} = \frac {8.35 kJ}{x}$

$x= 46.52 kJ$