The balanced equation for considered reaction can be written as follows
PH3(g)+4Cl2(g)→PCl5(g)+3HCl(l)
M(Cl2)⋅n(Cl2)m(Cl2)=M(PCl5)⋅n(PCl5)m(PCl5)
m(Cl2)=M(PCl5)⋅n(PCl5)m(PCl5)⋅M(Cl2)⋅n(Cl2)
M(Cl2)=2⋅35.453=70.906g/mol
M(PCl5)=1⋅30.974+5⋅35.453=208.239g/mol
m(Cl2)=208.239⋅10.015⋅70.906⋅4≈0.0204kg=20.4g
Answer: 20.4 g.
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