B. PH3 + 4Cl2 → PCl5 + 3HCl
n(PH3) = 10g/34g/mol = 0.294 mol
n(Cl2) = 15g/71g/mol = 0.211 mol
PH3 is in excess, Cl2 is the limiting reactant.
n(PCl5) = 0.211/4 = 0.053 mol
m(PCl5) = 0.053 mol*208.5 g/mol = 11.05 g
Percentage yield of PCl5 = 5.5g/11.05g = 0.498 = 49.8%
C. Wavelength: Λ = h/mv = 6.63*10-34kg·m2/s / 0.08kg·0.833m/s = 9.95·10-33 m
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