PH3+4Cl2→PCl5+3HClPH3+4Cl2 \to PCl5+3HClPH3+4Cl2→PCl5+3HCl
m(Cl2)=35.5g/mol∗2∗4∗15g208.22g/mol=20.46gm(Cl2)=\dfrac{35.5g/mol*2*4*15g}{208.22g/mol}=20.46gm(Cl2)=208.22g/mol35.5g/mol∗2∗4∗15g=20.46g
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