Solution.
Since it does not say how much barium acetate was taken, we assume that 100 grams of barium acetate were taken and the volumetric flask had a volume of 300 milliliters.
M((CH3COO)2Ba) = 255.43 g/mole
V(solution) = 300 mL
C = m/(M*V)
C = 100/(255.43*0.3) = 1.30 M
Answer:
C = 100/(255.43*0.3) = 1.30 M
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