Answer to Question #87200 in General Chemistry for Dj

Question

the volume of a gas is 400. ml sample of gas at 30.0 c. If the temperature is increased to 50.0 c without changing the pressure, what is the new volume of the gas?

Answer 1

To solve this problem,we use Gay-Lussac law for isobaric process:

$$V1/T1=V2/T2$$

Convert temperature to kelvin:30 c = 303 K

50 c = 323K

New volume of the gas:

$$V2=V1*T2/T1=400*323/303=426.4 ml$$