Answer to Question #87142 in General Chemistry for Monet

Question

Give the ΔH value for the combustion of propane as shown in the reaction C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)+2220 kJ.

Answer 1

The equation is written in the form

C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)+Q

Solution:

∆H= -Q= -2220 kJ

We must write the equation as

C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) ∆H= -2220 kJ.