Answer to Question #87004 in General Chemistry for Lim Yoona

Question #87004

For the following runs the concentration of the dyes were calculated as per below:

RUN [DYE] (mol L-1)
1 1.09 X 10-6
2. 2.43 X 10-6

Based on the above measurements the ln[DYE] for run 2 will be:

Expert's answer

ln[1.09 x 10-6]= 13.73

ln[2.43 x 10-6] = 12.93

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