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Answer to Question #86818 in General Chemistry for Lim Yoona
Question #86818
For the following runs the concentration of the dyes were calculated as per below:
RUN [DYE] (mol L-1)
1 1.09 X 10-6
2. 2.43 X 10-6
Based on the above measurements the ln[DYE] for run 2 will be:
RUN [DYE] (mol L-1)
1 1.09 X 10-6
2. 2.43 X 10-6
Based on the above measurements the ln[DYE] for run 2 will be:
Expert's answer
"1.ln[DYE]=ln[1.09*10^{-6}]=-13.7293"
"2.ln[DYE]=ln[2.43*10^{-6}=-12.9276"
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Students took 2.5 ml of a leaf extract and using column chromatography they separated carotene from chlorophyll. They collected carotene in a volumetric flask and made up their sample to the 25 mL line on the volumetric flask with hexane:acetone (3:2). Measured the absorbance of the purified carotene (collected in the volumetric flask), and found that it corresponded to a concentration of 0.031 mg mL-1. What was the concentration carotene in the original leaf extract in mg mL-1 ?
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