Answer to Question #86818 in General Chemistry for Lim Yoona

Question #86818

For the following runs the concentration of the dyes were calculated as per below:

RUN [DYE] (mol L-1)
1 1.09 X 10-6
2. 2.43 X 10-6

Based on the above measurements the ln[DYE] for run 2 will be:

Expert's answer

"1.ln[DYE]=ln[1.09*10^{-6}]=-13.7293"

"2.ln[DYE]=ln[2.43*10^{-6}=-12.9276"

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26.04.19, 08:30

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Lim Yoona

25.04.19, 04:21

Students took 2.5 ml of a leaf extract and using column chromatography they separated carotene from chlorophyll. They collected carotene in a volumetric flask and made up their sample to the 25 mL line on the volumetric flask with hexane:acetone (3:2). Measured the absorbance of the purified carotene (collected in the volumetric flask), and found that it corresponded to a concentration of 0.031 mg mL-1. What was the concentration carotene in the original leaf extract in mg mL-1 ?

Answer to Question #86818 in General Chemistry for Lim Yoona

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