Answer to Question #86816 in General Chemistry for Lim Yoona

Question

Determination of the new concentration of Dye and NaClO
A student has the following solutions available to them.

- Dye (1.23 x 10-6 mol L-1) – set to dispense in 1 mL aliquots.
- Deionised water – set to dispense in 0.5 mL aliquots
- NaClO (0.8 mol L-1) dispensed using a graduated pipette.

The student is assigned to Run 1.
Calculate the initial concentration of dye and bleach in this run. Answer to 2 significant figures.
-Run 1
- Dye (3.0mL)
-Deionised water (1.0mL)
-NaClO (0.50mL)
New concentration of Dye (mol L-1) ＝ ___ x 10^-7
New concentration of NaClO (mol L-1) ＝ ___ x 10^-2

Answer 1

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