Question

Dry ice is carbon dioxide in the solid state. 0.85 moles of dry ice are placed into a 4.47 L chamber that is maintained at 35 degrees C. What is the pressure in the chamber in atm after the dry ice turns into a gas? Round to two decimal places.

Answer 1

P(СO₂)×V(СO₂) = n(СO₂) × R × T(СO₂)

R = 0.082 L×atm×mol^-1×K^-1

T_K(СO₂) = t_C(СO₂) + 273.15 = (35 + 273.15) K = 308.15 K.

P(СO₂) = n(СO₂) × R × T(СO₂) / V(СO₂) = 0.85 mol × 0.082 L×atm×mol^-1×K^-1 × 308.15 K / 4.47 L = 4.8049 atm ≈ 4.80 atm.