Question

A.) A gas mixture contains 15.6 mol of C6H6 and 43.8 mol of H2.

Compute the mole fraction of C6H6 in the mixture.

XC6H6 = _________


B.) A catalyst is then added to the mixture, and the C6H6 starts to react with the H2 to give C6H12:

At a certain point in the reaction, 4.20 mol of C6H12 is present. Determine the mole fraction of C6H6 in the new mixture.
XC6H6= _________

Answer 1

A) XC6H6 =26.26%

B) XC6H6 = 8.974%