The specific thermal capacity of Al is "c = 0.902~\\frac{\\text{J}}{\\text{g}\\cdot\\degree\\text{C}};"
"{\\Delta}Q = cm{\\Delta}t = 0.902~\\frac{\\text{J}}{\\text{g}\\cdot\\degree\\text{C}}~*~10.9~\\text{g}~*~(36.7-20.0)~\\degree\\text{C} \\approx 164.19~\\text{J}."
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