Question #86521

What is the energy change when the temperature of 10.9 grams of solid aluminum is decreased from 36.7 degrees celsius to 20.0 degrees celsius

Expert's answer

The specific thermal capacity of Al is c=0.902 Jg°C;c = 0.902~\frac{\text{J}}{\text{g}\cdot\degree\text{C}};

ΔQ=cmΔt=0.902 Jg°C  10.9 g  (36.720.0) °C164.19 J.{\Delta}Q = cm{\Delta}t = 0.902~\frac{\text{J}}{\text{g}\cdot\degree\text{C}}~*~10.9~\text{g}~*~(36.7-20.0)~\degree\text{C} \approx 164.19~\text{J}.


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