Answer to Question #86418 in General Chemistry for Enci Peng

Question

A balloon is inflated with 0.35 moles of helium to a pressure of 1.63 atm. If the desired volume of the balloon is 1.15 L, what is the temperature in Kelvin? Round to two decimal places.

Answer 1

P(He)×V(He) = n(He) ×R×T(He)

R = 0.082 L×atm×mol^-1×K^-1

T(He) = P(He) × V(He) / (n(He) ×R) = 1.63 atm × 1.15 L / (0.35 mol × 0.082 L×atm×mol^-1×K^-1) = 65.3136 K ≈ 65.31 K.