Question

C(s) + 2H2(g) ---> CH4(g)

if the reaction produces 145 liters of CH4, how many liters of H2 were consumed?

Answer 1

The balanced equation for considered reaction can be written as follows

$C(s) + 2H_{2}(g) \rarr CH_{4}(g)$

$\frac{V(H_{2})}{N(H_{2}) \cdot V_m} = \frac{V(CH_{4})}{N(CH_{4}) \cdot V_m}$

V - volume

N - coefficient in chemical equation

V_m - molar volume

$V(H_{2}) = \frac{V(CH_{4}) \cdot N(H_{2})}{N(CH_{4})}$

$V(H_{2}) = \frac{145 \cdot 2}{1}=290 \; L$

Answer: 290 liters.