The balanced equation for considered reaction can be written as follows
"C(s) + 2H_{2}(g) \\rarr CH_{4}(g)"
"\\frac{V(H_{2})}{N(H_{2}) \\cdot V_m} = \\frac{V(CH_{4})}{N(CH_{4}) \\cdot V_m}"
V - volume
N - coefficient in chemical equation
Vm - molar volume
"V(H_{2}) = \\frac{V(CH_{4}) \\cdot N(H_{2})}{N(CH_{4})}"
"V(H_{2}) = \\frac{145 \\cdot 2}{1}=290 \\; L"
Answer: 290 liters.
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