n(NaOH) = C*V = 9.917*10-2mol/L*0.02976L = 0.29513*10-2 mol
n(HA) = n(NaOH)
M(HA) = m(HA)/n(HA) = 0.4145g/0.29513*10-2mol = 140.4 g/mol
B. 140.4 g/mol
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