Answer to Question #86107 in General Chemistry for Rahma

Question

What is the mass of magnesium phosphate which contains 0.47799 moles of magnesium ion. What is the mass of magnesium phosphate in grams.

Answer 1

n(Mg₃(PO₄)₂)= n(Mg²⁺) $/3$ = 0.47799$/3=0.15933 moles$

m(Mg₃(PO₄)₂= 0.15933moles*24.3 g/mol = 3.871719g