Question

What is the mass of magnesium phosphate which contains 0.47799 moles of magnesium ion. What is the mass of magnesium phosphate in grams.

Answer 1

n(Mg₃(PO₄)₂)= n(Mg²⁺) $/3$ = 0.47799$/3=0.15933 moles$

m(Mg₃(PO₄)₂= 0.15933moles*24.3 g/mol = 3.871719g