mol(Fe2+)=22.95mL∗0.1049mol1000mL=0.002407molmol(Fe2+)=22.95mL*\dfrac{0.1049mol}{1000mL}=0.002407molmol(Fe2+)=22.95mL∗1000mL0.1049mol=0.002407mol
mol(MnO4−)=0.002407mol∗1mol(MnO4−)5mol(Fe2+)=0.0004814molmol(MnO4-)=0.002407mol*\dfrac{1 mol(MnO4-) }{5mol(Fe2+)}=0.0004814molmol(MnO4−)=0.002407mol∗5mol(Fe2+)1mol(MnO4−)=0.0004814mol
c(MnO4−)=0.0004814mol0.03L=0.01605mol/Lc(MnO4-)=\dfrac{0.0004814mol}{0.03L}=0.01605 mol/Lc(MnO4−)=0.03L0.0004814mol=0.01605mol/L
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