Question #86055

A permanganate solution is standardized by titrating it with a 0.1049 M Fe2+ solution. The balanced net ionic equation for the reaction is:
MnO4-(aq) + 5Fe2+(aq)+8H3O+(aq)Mn2+(aq) + 5Fe3+(aq)+12H2O(l)

If 22.95 mL of the 0.1049 M Fe2+ solution is required to react completely with 30.00 mL of the permanganate solution, calculate the concentration of the permanganate solution.

__________ M

Expert's answer

mol(Fe2+)=22.95mL∗0.1049mol1000mL=0.002407molmol(Fe2+)=22.95mL*\dfrac{0.1049mol}{1000mL}=0.002407mol


mol(MnO4−)=0.002407mol∗1mol(MnO4−)5mol(Fe2+)=0.0004814molmol(MnO4-)=0.002407mol*\dfrac{1 mol(MnO4-) }{5mol(Fe2+)}=0.0004814mol

c(MnO4−)=0.0004814mol0.03L=0.01605mol/Lc(MnO4-)=\dfrac{0.0004814mol}{0.03L}=0.01605 mol/L


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