c(HClO4)=c(Ca(OH)2)∗V(Ca(OH)2)V(HClO4)=0.193M∗20.6mL27mL=0.147mol/Lc(HClO4)=\dfrac{c(Ca(OH)2)*V(Ca(OH)2)}{V(HClO4)}=\dfrac{0.193M*20.6mL}{27mL}=0.147 mol/Lc(HClO4)=V(HClO4)c(Ca(OH)2)∗V(Ca(OH)2)=27mL0.193M∗20.6mL=0.147mol/L
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