Answer to Question #86048 in General Chemistry for thomas

Question

What volume of a 0.354 M perchloric acid solution is required to neutralize 20.6 mL of a 0.193 M sodium hydroxide solution?

__________ mL perchloric acid

Answer 1

HClO₄ + NaOH -> NaClO₄ + H₂O

c=n/V, then n= c*V

n(NaOH) = 0.0206 L* 0.193 mol/L = 0.00398 mol

According to equation mole ratio n( HClO₄):n(NaOH)= 1:1, then n(HClO₄)=n(NaOH) = 0.00398 mol

c=n/V, then V= n/c = 0.00398 mol/0.354 mol/L = 0.0112 L= 11.2 mL

Answer: 11.2 mL