Answer to Question #86047 in General Chemistry for thomas

Question

Calculate the number of milliliters of 0.544 M NaOH required to precipitate all of the Mg2+ ions in 140 mL of 0.683 M Mg(NO3)2 solution as Mg(OH)2. The equation for the reaction is:

Mg(NO3)2(aq) + 2NaOH(aq) Mg(OH)2(s) + 2NaNO3(aq)

_________ mL NaOH

Answer 1

351.54 mL.