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Answer to Question #86038 in General Chemistry for thomas

Question #86038
How many milliliters of an aqueous solution of 0.126 M iron(II) nitrate is needed to obtain 16.3 grams of the salt?

________ mL
1
Expert's answer
2019-03-15T02:34:04-0400

n(Fe(NO3)2)="\\dfrac{16.3g}{179.85g\/mol} = 0.09 mol"

V="\\dfrac{1000mL*0.09 mol}{0.126M} = 714.28 mL"


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