Answer to Question #86038 in General Chemistry for thomas

Question #86038
How many milliliters of an aqueous solution of 0.126 M iron(II) nitrate is needed to obtain 16.3 grams of the salt?

________ mL
1
Expert's answer
2019-03-15T02:34:04-0400

n(Fe(NO3)2)="\\dfrac{16.3g}{179.85g\/mol} = 0.09 mol"

V="\\dfrac{1000mL*0.09 mol}{0.126M} = 714.28 mL"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS