Answer to Question #85972 in General Chemistry for thomas

Question #85972

Calculate the volume of 8.46×10-2 M potassium hydroxide required to neutralize 15.3 mL of a 0.172 M nitric acid solution.

________ mL

Expert's answer

V(KOH)*N(KOH) = V(HNO3)*N(HNO3)

V(KOH) = V(HNO3)*N(HNO3)/N(KOH)

V(KOH) = 15.3*0.172/0.0842 = 31.106 (ml(KOH))

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