n(H2)= 7.8g"\/ 2 {g \\over mol} = 3.9 mol"
n(O2)= "13.7g\/(15.99 {g \\over mol}*2) = 0.428 mol"
2H2 + O2 "\\to" 2H2O
n(H2O)= 2*n(O2)= 0.428*2=0.856 mol
m(H2O)=n(H2O)*M(H2O) = "0.856mol*18.01 {g \\over mol} = 15.42 g"
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