Question

If a system has 3.00 × 102 kcal of work done to it, and releases 5.00 × 102 kJ of heat into its surroundings, what is the change in internal energy of the system?

Answer 1

Answer on Question #85873 – Chemistry – Inorganic Chemistry

If a system has $3.00 \times 10^{2}$ kcal of work done to it, and releases $5.00 \times 10^{2}$ kJ of heat into its surroundings, what is the change in internal energy of the system?

Solution:

$3.00 \times 10^{2} \mathrm{kcal} \times 4.19 \mathrm{kJ} / \mathrm{kcal} = 1.26 \times 10^{3} \mathrm{kJ}$

Change in internal energy $= 1.26 \times 10^{3} \mathrm{kJ} - 5.00 \times 10^{2} \mathrm{kJ} = +7.57 \times 10^{2} \mathrm{kJ}$

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