Answer to Question #85786 in General Chemistry for kellynn

Question #85786

How many moles of carbon are in 3.08*10^23 molecules of C6H12O6

Expert's answer

n(C₆H₁₂O₆) = N(C₆H₁₂O₆)/N_A = 3.08*10^23 / 6.02*10^23 mol^-1 ≈ 0.5116 mol.

n(C) = 6*n(C6H12O6) = 6*0.5116 mol = 3.0696 mol ≈ 3.07 mol.

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