Answer to Question #85757 in General Chemistry for Chamberlyn

Question #85757

What mass of iron (0.11 cal/g) would need 1450 cal of energy in order to raise its temperature by 19.7 C?

Expert's answer

m="Q\/c*\\Delta T" = "1450cal\/(0.11cal\/g* 19.7\u00baC)=669.12 g"

Answer: 669.12g iron.

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