Answer in General Chemistry for Chamberlyn #85757

Question #85757

What mass of iron (0.11 cal/g) would need 1450 cal of energy in order to raise its temperature by 19.7 C?

Expert's answer

m= $Q/c*\Delta T$ = $1450cal/(0.11cal/g* 19.7ºC)=669.12 g$

Answer: 669.12g iron.

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