2NH3 + H3PO4 = (NH4)2HPO4
M (H3PO4) = 3 + 31 + 64 = 98 g/mol
n (H3PO4) = 2.8/98 = 0.029 mole
n (H3PO4) = n ((NH4)2HPO4)
M ((NH4)2HPO4) = (14+4)*2+1+31+16*4 = 132 g /mol
m ((NH4)2HPO4) = 0.029*132 = 3.8 g
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