Question #85335

How many atoms are in a 591 g sample of gold?

Expert's answer

Answer on Question #85335 – Chemistry – General Chemistry

Task:

How many atoms are in a 591 g sample of gold?

Solution:


Ar(Au)=197amuM(Au)=Ar(Au)=197gmoln(Au)=m(Au)M(Au)=591g197g/mol=3mol\begin{array}{l} Ar(Au) = 197 \, amu \\ M(Au) = Ar(Au) = \frac{197 \, g}{mol} \\ n(Au) = \frac{m(Au)}{M(Au)} = \frac{591 \, g}{197 \, g/mol} = 3 \, mol \\ \end{array}


There are 6.022×10236.022 \times 10^{23} molecules per mole, so


N(Au)=n(Au)Na=3mol6.0221023=18.06610231.81024N(Au) = n(Au) \cdot N_a = 3 \, mol \cdot 6.022 \cdot 10^{23} = 18.066 \cdot 10^{23} \approx 1.8 \cdot 10^{24}


Answer: 1.8×10241.8 \times 10^{24} atoms are in a 591 g sample of gold

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