Question

The molecular formula of allicin, the compound responsible for the characteristic smell of garlic, is C6H10OS2.
What is the molar mass of allicin?
How many moles of allicin are present in 2.80 mg of this substance?
How many molecules of allicin are in 2.80 mg of this substance?
How many H atoms are present in 2.80 mg of allicin?

Answer 1

M (C₆H₁₀OS₂) = 6*12+10*1+1*16+2*32 = 162 g/mole

2.80 mg = 0.0028 g

n = m/M = 0.0028 g / 162 g/mole = 0.00001728 moles

N = n*Nₐ = 0.000017 moles * 6.02*10²³ = 0.000104*10²³ molecules

N atoms of "H" = 0.000104*10²³ molecules * 10 = 0.00104 * 10²³

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