Question #84834

You measure 3.10 mL of a 50% NaOH solution by weight (its density is 1.53 g mL-1) and dilute it to 500 mL total volume. What is the concentration of this NaOH solution? Write your answer to four decimal places (X.XXXX).
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Expert's answer

2019-02-04T09:41:07-0500

Question #84834, Chemistry / General chemistry

You measure 3.10 mL of a 50% NaOH solution by weight (its density is 1.53 g mL-1) and dilute it to 500 mL total volume. What is the concentration of this NaOH solution? Write your answer to four decimal places (X.XXXX).

Solution


m(NaOH)=V(NaOH)soldw=3.101.530.5=2,3715 (g)m(\mathrm{NaOH}) = V(\mathrm{NaOH})_{\mathrm{sol}} \cdot d \cdot w = 3.10 \cdot 1.53 \cdot 0.5 = 2,3715 \text{ (g)}M(NaOH)=23+16+1=40 (g/mol)M(\mathrm{NaOH}) = 23 + 16 + 1 = 40 \text{ (g/mol)}n(NaOH)=m/M=2.3715/40=0,0593 (mol)n(\mathrm{NaOH}) = m / M = 2.3715 / 40 = 0,0593 \text{ (mol)}c(NaOH)=n/V=0,0593/0.5=0,1186 (M)c(\mathrm{NaOH}) = n / V = 0,0593 / 0.5 = 0,1186 \text{ (M)}


Answer


c(NaOH)=0,1186 Mc(\mathrm{NaOH}) = 0,1186 \text{ M}


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