Heat absorbed by water (Q1) = heat released by copper (Q2)
-Q1 = Q2
c1m1ΔΤ = c2m2ΔΤ
Specific heat of copper c(copper) = 0.385 J/g*C
Specific heat of water c(water) = 4.184 J/g*C
- 4.184 J/g*C *m1 (22C -18C) = 0.385 J/g*C *850 g * (22C - 175C)
m1 = 2991.7 g
Answer: 2991.7 g
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