C(NH3)= 6mol/2L = 3 mol/L
3*0.4=1.2 mol/L NH3 was decomposed
2NH3 = N2 + 3H2
At equilibrium:
[NH3]=3-1.2=1.8 mol/L
[N2]=0.6 mol/L
[H2]=1.8 mol/L
Kc = [N2]•([H2]^3)/[NH3]^2 = 1.08
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