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Answer to Question #84531 in General Chemistry for jessica

Question #84531
What would be the mass of 62.32 L of Mg(OH)2 ?
1
Expert's answer
2019-01-28T05:32:40-0500

Formula:

p=m/V, m=p x V.

p=2,34 g/cm3.

V=62,32 L=62320 ml

m=2.34 x 62320 = 145828.8 gramm

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