Answer to Question #84288 in General Chemistry for Breezy

Question

How many liters of NH₃, at STP, will react with 8.5 g O₂ to form NO₂ and water?

Answer 1

4NH3 + 7O2 = 4NO2 + 6H2O balanced equation

moles O2 used = 8.5 g O2 x 1 mole/32 g = 0.266 moles O2

moles NH3 needed = 0.266 mol O2 x 4 mol NH3/7 mol O2 = 0.152 moles

At STP, 0.152 moles x 22.4 L/mole = 3.4 liters of NH3