Answer to Question #84135 in General Chemistry for Prince somera

Question #84135

What mass of solute is present in 40 mL of 6.0mol/L sulfuric acid (H2SO4) solution?

Expert's answer

V(H2SO4)=40ml=0,04L

CM=6 mol/L

m(H2SO4)-?

n=Cm*V= 6*0.04=0.24 mol

M(H2SO4)=98 g/mol

m= M*n=98*0.24=23,52 g

Answer:m=23,52 g

Learn more about our help with Assignments: Chemistry

No comments. Be the first!

Who Can Help Me with My Assignment

There are three certainties in this world: Death, Taxes and Homework Assignments. No matter where you study, and no matter…
How to Finish Assignments When You Can’t

Crunch time is coming, deadlines need to be met, essays need to be submitted, and tests should be studied for.…
How to Effectively Study for a Math Test

Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…